WebJun 23, 2011 · You can use string builder to achieve this. int length = value.Length; var lastString = value [length - 1]; if (lastString == 'Z') { if ( (length - 2) >= 0) ++value [length - 2]; else value.Append ('A'); value.Replace ("Z", "A"); } else ++value [length - 1]; Share Improve this answer Follow edited Apr 27, 2016 at 6:06 WebSep 5, 2016 · int charToDigit (char character) { return character-64; //or character-0x40 if you prefer hex } This will simply convert the ASCII char to its corresponding int and pull it down to 1. Since 'A' is 65 or 0x41 in ASCII, it will result in a 1 when subtracting 64./0x40. Subtract 0x40 if you want 'A' to be 0. Share Improve this answer Follow
Find letter’s position in Alphabet using Bit operation
WebIf the purpose of the dictionary is to find the nth letter of alphabet, simply use (char)('A' - 1 + n) for upper-case and (char)('a' - 1 + n) for lower-case. No dictionary needed. No dictionary needed. WebAug 25, 2013 · int number = (int)chr; However, the character 'A' is actually represented by the number 65, 'B' 66, and so on (see ASCII ), so you'll have to subtract that from your input to get the intended value: int value = number - 65; Or if you prefer: int value = number - … the problem with student loan debt
c# - Assign integer value to letter - Stack Overflow
WebApr 12, 2024 · A Computer Science portal for geeks. It contains well written, well thought and well explained computer science and programming articles, quizzes and practice/competitive programming/company interview Questions. WebNov 25, 2016 · var alphabet = Enumerable.Range (0, 26).Select (i => Convert.ToChar ('A' + i)); Share Improve this answer Follow answered May 3, 2016 at 10:25 shankar.siva 189 2 14 Add a comment 5 Enumerable.Range (65, 26).Select (a => new { A = (char) (a) }).ToList ().ForEach (c => Console.WriteLine (c.A)); Share Improve this answer Follow WebJun 25, 2024 · Add a comment. 1. public static string IntToLetters (int value) { string result = string.Empty; while (--value >= 0) { result = (char) ('A' + value % 26 ) + result; value /= 26; } return result; } To meet the requirement of A being 1 instead of 0, I've added -- to the while loop condition, and removed the value-- from the end of the loop, if ... signal horn refill